Porisma

Discussion questions · Section 1 of 2

Questions 1–6 in this collection

Write vector and Cartesian equations without dividing by zero · Recover a point and direction from Cartesian relations · +4 more

All chapter practiceAll discussion questions
  1. 1

    Find a vector equation and cartesian equation of the following lines:

    (a) passing through the point with position vector 7i+2j−4k7\mathbf i+2\mathbf j-4\mathbf k and parallel to to i−3j+k\mathbf i-3\mathbf j+\mathbf k

    (b) passing through the points (2,−2,1)(2,-2,1) and (0,4,9)(0,4,9)

    (c) passing through the point with position vector 7i7\mathbf i and parallel to the line r=(2−p)i+pj+5k\mathbf r=(2-p)\mathbf i+p\mathbf j+5\mathbf k.

    CJC · Discussion · Question 1

  2. 2

    Convert the equations of following lines to their vector equation form:

    (a) 3y=2x−6=z−123y=2x-6=\dfrac{z-1}{2}

    (b) x+5=2−4yx+5=2-4y, z=3z=3

    CJC · Discussion · Question 2

  3. 3

    Given a line with vector equation r=(i+2j+3k)+λ(i+2j+5k)\mathbf r=(\mathbf i+2\mathbf j+3\mathbf k)+\lambda(\mathbf i+2\mathbf j+5\mathbf k), λ∈R\lambda\in\mathbb R,

    (i) show that point A(3,6,13)A(3,6,13) lies on the line,

    (ii) find the perpendicular distance from point B(1,7,4)B(1,7,4) to the line.

    CJC · Discussion · Question 3

  4. 4

    Given three points A(0,2,7)A(0,2,7), B(5,−3,2)B(5,-3,2) and C(1,1,1)C(1,1,1), find the position vector of the point RR on ABAB such that CRCR is perpendicular to ABAB. Hence find the perpendicular distance from CC to ABAB and the position vector of the reflection of CC in ABAB.

    CJC · Discussion · Question 4

  5. 5

    Find whether the following pairs of lines are parallel, intersecting or skew. If they intersect, find the point of intersection and the acute angle between the lines.

    (a) r=(1,−1,1)+λ(3,4,1)\mathbf r=(1,-1,1)+\lambda(3,4,1), λ∈R\lambda\in\mathbb R, and r=(1,2,3)+μ(9,12,3)\mathbf r=(1,2,3)+\mu(9,12,3), μ∈R\mu\in\mathbb R.

    (b) r=(1,0,3)+s(2,1,1)\mathbf r=(1,0,3)+s(2,1,1), s∈Rs\in\mathbb R, and r=(2,−1,1)+t(1,−2,0)\mathbf r=(2,-1,1)+t(1,-2,0), t∈Rt\in\mathbb R.

    (c) r=4i+8j+3k+α(i+2j+k)\mathbf r=4\mathbf i+8\mathbf j+3\mathbf k+\alpha(\mathbf i+2\mathbf j+\mathbf k), α∈R\alpha\in\mathbb R, and r=7i+6j+5k+β(6i+4j+5k)\mathbf r=7\mathbf i+6\mathbf j+5\mathbf k+\beta(6\mathbf i+4\mathbf j+5\mathbf k), β∈R\beta\in\mathbb R.

    (d) r=(4,2,1)+λ(2,1,−2)\mathbf r=(4,2,1)+\lambda(2,1,-2), λ∈R\lambda\in\mathbb R, and the z-axis.

    [Hint: The z-axis has equation r=γ(0,0,1)\mathbf r=\gamma(0,0,1), γ∈R\gamma\in\mathbb R.]

    CJC · Discussion · Question 5

  6. 6

    Given the two lines l1:4(1−x)=y=2z+4l_1:4(1-x)=y=2z+4 and l2:8−4x=y+3=2zl_2:8-4x=y+3=2z, explain why they are parallel. Find the distance between the two lines.

    CJC · Discussion · Question 6

Back to all questions