An exponential reflected at its zero

(i) Sketch y=∣(1/3)2x−18∣y=|(1/3)^{2x}-18|, finding exact intercepts. marks

(ii) Without a calculator, solve ∣(1/3)2x−18∣≤9|(1/3)^{2x}-18|\le9 with full working, giving the exact interval or intervals in their simplest form. marks

[2022/ACJC/Prelim/I/2]

Total marks: 6

Solution

(i)

Sketching a modulus curve

Sketch the graph of y=∣(13)2x−18∣y=\left|\left(\tfrac13\right)^{2x}-18\right|, finding the exact intercepts.

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Hint

  1. (13)2x=3−2x\left(\frac13\right)^{2x}=3^{-2x}: an exponential decay.

  2. Intercepts: x=0x=0 for the yy-intercept; set the inside to 0 for the xx-intercept.

  3. The inside tends to −18-18 as x→∞x\to\infty, so the modulus gives the asymptote y=18y=18.

Absolute exponential graph
Absolute exponential graphScroll across to see the full diagram.

Answer · (i)

Intercepts (0,17)(0,17) and (−ln⁡18/(2ln⁡3),0)(-\ln18/(2\ln3),0); horizontal asymptote y=18y=18.

Explore the idea

Drop by 18, then fold

Subtract 18 from the decaying exponential, then take the absolute value.

Teal: y = 3^(−2x). No comparison overlay.

Start: y = 3^(−2x)

The decaying exponential, crossing the yy-axis at 1.

  • Graph at the selected step
Ideas to try
How does the yy-intercept change between steps 2 and 3?
(ii)

Absolute-value inequalities

Without a calculator, solve ∣(13)2x−18∣≤9\left|\left(\tfrac13\right)^{2x}-18\right|\le9 with full working, giving the exact interval or intervals in their simplest form.

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Hint

  1. ∣u∣≤9|u|\le9 means −9≤u≤9-9\le u\le9.

  2. Add 18 to isolate 3−2x3^{-2x}.

  3. Write the bounds as powers of 3 and compare exponents.

Answer · (ii)

−3/2≤x≤−1-3/2\le x\le-1.

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Where is the folded curve below y = 9?

Switch on 'Solution' to shade the strip between the curve and y = 9, from x = −3/2 to x = −1.

Switch on a feature to add it to the sketch and see how it is found. A full-mark sketch shows all of them.

  • Y = |3^(−2x) − 18|
  • Y = 9
  • Intersections and the solution
Ideas to try
Why does the line y = 9 meet the folded curve exactly twice?