Reuse two basic integrals and a radical substitution
(a)(i) Find . marks
(ii) Find . marks
(iii) Using (i) and (ii), find . marks
(b)(i) By using , find . marks
(ii) Find the exact value of , leaving the answer , where are integers to be determined. marks
[2016/VJC/Promo/11]
Solution
If this part uses an earlier result, revisit (a)(iii) Linear combination or open all working together.
(b)(i)
Radical substitution
By using , find .
Hint
so Differentiate to obtain . Equivalently, for , differentiate and invert its derivative. Use ; then , which justifies the logarithm without modulus.
Divide to get a polynomial plus a simple fraction.
Leaving the answer in
For an indefinite integral in the final answer must be in .
Answer · (b)(i)
.
; derivative on x>0.
Substitute
.
Divide
Polynomial long division.
Integrate
Return to .
Explore the idea