Use identities for the integral and geometry for the regions

Graphs y=e²ˣ and y=(x+1)², intersection (−1.2785,0.07754), common y-intercept 1Source-given figure redrawn with D3. Graphs y=e²ˣ and y=(x+1)², intersection (−1.2785,0.07754), common y-intercept 1. Only labels supplied in the original question are included.xyO(−1.2785, 0.07754)1y=(x+1)²y=e²ˣ
Question diagram 1
Graphs y=e²ˣ and y=(x+1)², intersection (−1.2785,0.07754), common y-intercept 1Source-given figure redrawn with D3. Graphs y=e²ˣ and y=(x+1)², intersection (−1.2785,0.07754), common y-intercept 1. Only labels supplied in the original question are included.xyO(−1.2785, 0.07754)1y=(x+1)²y=e²ˣ

Given exponential and quadratic graphs with printed intersection and common intercept.

Curve C and line L enclosing shaded S; labelled intersection (−2,−1)Source-given figure redrawn with D3. Curve C and line L enclosing shaded S; labelled intersection (−2,−1). Only labels supplied in the original question are included.xyOCSL(−2, −1)
Question diagram 2
Curve C and line L enclosing shaded S; labelled intersection (−2,−1)Source-given figure redrawn with D3. Curve C and line L enclosing shaded S; labelled intersection (−2,−1). Only labels supplied in the original question are included.xyOCSL(−2, −1)

Given curve C and line L enclosing shaded region S, with printed intersection.

(a) Find ∫(cot⁡62x+cot⁡42x−sin⁡(x/2)sin⁡(3x/2))dx\int(\cot^62x+\cot^42x-\sin(x/2)\sin(3x/2))dx. marks

(b) The diagram shows y=e2xy=e^{2x} and y=(x+1)2y=(x+1)^2, intersection (−1.2785,0.07754)(-1.2785,0.07754) and yy-intercept 1. R is the finite region bounded by both curves. Find the volume when R is rotated 2π2\pi about the yy-axis, to 4 decimal places. marks

(c) C: x=2(sin⁡(t/2)−cos⁡(t/2))x=2(\sin(t/2)-\cos(t/2)), y=sin⁡(t/2)+cos⁡(t/2)y=\sin(t/2)+\cos(t/2), −3π/2≤t≤−π/2-3\pi/2\le t\le-\pi/2. Line L: y=−2x−5y=-2x-5, meets C at (−2,−1)(-2,-1). S is enclosed by L,C and the xx-axis as shown.

(i) Show C’s xx-intercept is −22-2\sqrt2. marks

(ii) Find the exact area of S. marks

[2020/ASRJC/Prelim/II/4]

Total marks: 14

Solution

If this part uses an earlier result, revisit (a) Trigonometric integration or open all working together.

(b)

Volume of revolution

The curves y=e2xy=e^{2x} and y=(x+1)2y=(x+1)^2 intersect at (−1.2785, 0.07754)(-1.2785,\,0.07754) and cross the yy-axis at (0,1)(0,1). The region RR is the finite region bounded by the two curves. Find the volume when RR is rotated through 2π2\pi radians about the yy-axis, giving your answer to 4 decimal places.

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Hint

  1. RR lies to the left of the yy-axis. At each height yy, which curves bound it?

  2. Below the exact intersection height (about 0.07754), the left edge is the parabola's left branch. Above it, the left edge is the exponential.

  3. The right edge is the parabola's right branch throughout. Use washers: (outer)² − (inner)².

Answer · (b)

V=0.5593V=0.5593 cubic units (4 d.p.).

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Open interactive exploration

A thin pot with a curved wall

R sits to the left of the y-axis; reflecting it gives the same solid and keeps the picture on the right. The outer wall changes curve at the intersection point.

Open the interactive view to explore this geometry in 3D.