Plane intersections and orthogonal directions
Planes are and .
(i) Find their acute angle. marks
(ii) Obtain a vector equation of intersection line . marks
Another line is , , m real.
(iii) If and intersect at , find m. marks
(iv) Show are perpendicular for all m. marks
[2010/DHS/Prelim/II/4]
Solution
Angle between planes
Find the acute angle between and .
Hint
The angle between planes is the acute angle between their normals.
The angle between two planes equals the angle between their normals (acute).
Answer · (i)
.
Dot product
.
Magnitudes
, .
Angle
Inverse cosine.
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Line of intersection
Find a vector equation of the line where and meet.
Hint
Direction .
Find one common point by setting .
The line is perpendicular to both normals: use the cross product.
Answer · (ii)
.
Direction
.
A point
Solve the two equations.
The line
Alternative: solve with a free coordinate
On the source calculator, choose Apps → PlySmlt2 → Simultaneous Eqn Solver, with 2 equations and 3 unknowns. Enter the two plane equations and solve, using . Letting gives the same line as the cross-product construction.
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Line meeting a plane
, meets at . Find .
Hint
The point lies on : substitute into .
The condition is that the point is on the plane.
Answer · (iii)
.
Substitute
Point on .
Solve
Perpendicular directions
Show that and are perpendicular for all .
Hint
: .
Perpendicular directions do not mean the lines meet.
Answer · (iv)
: directions are orthogonal for every .
The lines intersect only for ; otherwise they are skew, not intersecting perpendicular lines.
Directions
From the line equations.
Dot product
Independent of .
Check when the lines actually meet
The remaining coordinate then requires . Only for this value are the lines intersecting and perpendicular; at other values they are skew with orthogonal directions.
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