A wardrobe model from lines and planes
A home interior designer is looking to design a pull-down wardrobe lift. To test his concept, the designer built a small-scale model of it, in which points are defined relative to a corner of the model at . The rods used in the model can be modelled by equations of straight lines.
The main rod can be modelled by the line with equation , . Another rod, line , passes through the points and .
(a) A supporting wire connects to a point on such that is perpendicular to . Find the position vector of . marks
(b) A retractable rod, line , is placed such that it can be modelled by reflecting about . Find a vector equation of . marks
The panels of the small-scale model can be modelled by equations of planes. The main panel, plane , contains the main rod and an attachment point . A side panel, plane , can be represented by the equation .
(c) Show that can be represented by the cartesian equation . marks
(d) A structural rod, line , needs to be placed at the intersection between . Find a vector equation of . marks
(e) A decorative plank, plane , has equation , where . If the distance between is exactly units, find the possible values of . marks
[2023/TMJC/Prelim/I/9]
Solution
Foot of a perpendicular
and . Find the foot of the perpendicular from to .
Hint
with .
The perpendicular condition is on .
Answer · (a)
.
Vector
.
Perpendicular
Dot with .
Foot
Alternative: project from the point
Use and direction . Both vectors in the projection angle are directed away from ; reversing only one would change the sign. This gives the same foot .
Explore the idea
Reflecting a line
Find a vector equation of , the reflection of (through and ) in .
Hint
is the midpoint of and its image .
passes through and .
is on : it does not move.
Answer · (b)
.
Image of
Midpoint.
Direction
.
Alternative: reflect relative to
Use the midpoint theorem with vectors based at rather than at the origin. The reflected line again passes through the fixed point .
The line
Through (on the mirror line).
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Plane through a line and a point
contains and . Show .
Hint
Normal .
Use two vectors that lie in the plane.
Answer · (c)
.
Vectors
Both lie in the plane.
Normal
Cross product.
Constant
Using .
Equation
Explore the idea
Intersection of planes
. Find a vector equation of .
Hint
Direction .
Find a common point.
The line is perpendicular to both normals.
Answer · (d)
.
Direction
Cross product.
A common point
Solve.
The line
The point also satisfies both planes and equals this point at . Thus , , is an equivalent equation.
Alternative: use the simultaneous-equation solution
Solve the two plane equations with one free coordinate, or use the source calculator's two-equation, three-unknown solver. Setting recovers the same vector line.
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Parallel planes at a given distance
is from . Find , .
Hint
Parallel to : .
Distance between and .
The plane can lie on either side of .
Answer · (e)
; or .
Parallel
Nonparallel planes intersect and have zero shortest separation. The given positive distance therefore forces parallel planes and proportional normals.
Rewrite
Divide by 3.
Distance
.
Solve
Two planes, one each side of .
Alternative: project a vector joining the planes
Here lies on and lies on . Project their connecting vector onto the common unit normal and equate its length to ; this gives the same two values of .
Explore the idea