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Complex numbers and the Argand plane

Practice section 8 of 9

Questions 43–48 in this collection

Practice questions

Review practice · 3 of 6

Read cubic roots and rotate roots of a complex quadratic

Do not use a graphic calculator in answering this question.

(a) The diagram shows y=f(x)y=f(x) for a cubic polynomial with real coefficients. What can be said about all roots of f(x)=0f(x)=0? [2]

(b) The equation 2z2−(7+6i)z+11+ic=02z^2-(7+6i)z+11+ic=0, where cc is a nonzero real number, has a root z=3+4iz=3+4i. Show that c=−2c=-2 and determine the other root in Cartesian form. Hence find the roots of 2w2+(−6+7i)w−11+2i=02w^2+(-6+7i)w-11+2i=0. [6]

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Qualitative cubic sketch with an increasing right-hand end and decreasing left-hand end. It crosses the x-axis once on the negative side, has a local maximum on the y-axis above the x-axis, then a local minimum to the right that also stays above the x-axis. Neither turning point touches the axis. The axes have no numerical scales.
Qualitative cubic sketch with an increasing right-hand end and decreasing left-hand end. It crosses the x-axis once on the negative side, has a local maximum on the y-axis above the x-axis, then a local minimum to the right that also stays above the x-axis. Neither turning point touches the axis. The axes have no numerical scales.
Qualitative cubic sketch with an increasing right-hand end and decreasing left-hand end. It crosses the x-axis once on the negative side, has a local maximum on the y-axis above the x-axis, then a local minimum to the right that also stays above the x-axis. Neither turning point touches the axis. The axes have no numerical scales.

[2017/DHS/I/8(a),(b)]

CJC · Review problems · Question 8

Solution

Review practice · 4 of 6

Distinguish a modulus square from a complex square

(a) The complex numbers z,wz,w satisfy z+w∗+5i=10z+w^*+5i=10 and ∣w∣2=z+18+i|w|^2=z+18+i. Find zz and ww. [4]

(b)(i) Given that 2+i2+i is a root of z2−5z+7+i=0z^2-5z+7+i=0, find the second root in Cartesian form, showing your working. [2]

(b)(ii) Hence find the roots of −iw2+5w+7i−1=0-iw^2+5w+7i-1=0. [2]

[2017/CJC/II/4(a),(b)]

CJC · Review problems · Question 9

Solution

Review practice · 6 of 6

Solve coupled equations by three algebraic methods

Without the use of a calculator, find the complex numbers z,wz,w satisfying z−wi=3z-wi=3 and z2−w+6+3i=0z^2-w+6+3i=0. [6]

[2017/SAJC/II/1]

CJC · Review problems · Question 11

Solution

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