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Vectors: lines and perpendicular feet

Practice section 1 of 6

Questions 1–6 in this collection

Practice questions

Worked example · 1 of 6

Build a line by extending and splitting a displacement

The line l passes through P and Q. The position vector of P is p\mathbf p and PQ→=m\overrightarrow{PQ}=\mathbf m.

(a) Express the position vector of Q in terms of p,m.

(b) E lies on PQ produced with PE=3 PQ; F is the midpoint of PQ; G lies on QP produced with PG:PQ=2:1. (i) Mark E,F,G on the diagram. (ii) Express their position vectors in terms of p,m.

(c) What can you conclude about the position vector of any point R on l?

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The source line l passes through P and Q, with origin O below it, position vector OP=p and displacement PQ=m. The positions of E,F,G are to be supplied.
The source line l passes through P and Q, with origin O below it, position vector OP=p and displacement PQ=m. The positions of E,F,G are to be supplied.
The source line l passes through P and Q, with origin O below it, position vector OP=p and displacement PQ=m. The positions of E,F,G are to be supplied.

CJC · Lecture · Exploration Activity

Solution

Self-practice · 4 of 6

Practise five conversions between vector and Cartesian forms

Self-Practice 7:

(a) Convert r=(2,3,−1)+λ(3,4,5)\mathbf r=(2,3,-1)+\lambda(3,4,5), λ real, to Cartesian form.

(b) Convert r=i+j+λ(i+5k)\mathbf r=\mathbf i+\mathbf j+\lambda(\mathbf i+5\mathbf k), λ real, to Cartesian form.

(c) Convert (x−1)/2=y/3=z−4(x-1)/2=y/3=z-4 to a vector equation.

(d) Convert (1−x)/3=(2y−1)/5(1-x)/3=(2y-1)/5, z=4, to a vector equation.

(e) Give vector and Cartesian equations for the line through A with position vector a=i−3j+2k\mathbf a=\mathbf i-3\mathbf j+2\mathbf k, parallel to m=5i+4j−k\mathbf m=5\mathbf i+4\mathbf j-\mathbf k.

CJC · Lecture · Self-Practice 7

Solution

Worked example · 5 of 6

Check a point using one consistent parameter

Determine whether (−1,3,−3)(-1,3,-3) lies on the line in Example 21: r=(5,1,−2)+λ′(6,−2,1)\mathbf r=(5,1,-2)+\lambda'(6,-2,1), λ′∈R\lambda'\in\mathbb R, equivalently (x−5)/3=1−y=2z+4(x-5)/3=1-y=2z+4.

CJC · Lecture · Example 22

Solution

Worked example · 6 of 6

Find a perpendicular foot, shortest distance and reflected point

The point is P=(1,1,−1)P=(1,1,-1) and the line is r=(1,2,3)+λ(1,2,1)\mathbf r=(1,2,3)+\lambda(1,2,1), λ∈R\lambda\in\mathbb R.

(i) Find the coordinates of the foot of the perpendicular from P to the line.

(ii) Deduce the shortest distance from P to the line.

(iii) Find the position vector of the image of P in the line.

CJC · Lecture · Example 23

Solution

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