Porisma

Review practice · Section 2 of 3

Questions 7–12 in this collection

Recover plane constants from an intersection line · Transform a plane after finding intersections and parallel offsets · +4 more

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  1. 7

    Planes p1,p2 are 2x−5y+3z=32x-5y+3z=3 and 3x+λy+6z=μ3x+\lambda y+6z=\mu.

    (i) They intersect in l:r=(4,−2,−5)+s(−2,1,3)\mathbf r=(4,-2,-5)+s(-2,1,3), s real. Show λ=−12 and find μ. marks

    Plane p3 is 5x+8y+tz=125x+8y+tz=12.

    (ii) Using(i), find the exact t if p3 does not intersect l. marks

    (iii) Plane p4 contains l and (1,−1,2). Find its Cartesian equation. marks

    [2010/RI(JC)/I/11(modified)]

    CJC · Review problems · Question 7

  2. 8

    A has position vector −i−11j+2k-\mathbf i-11\mathbf j+2\mathbf k. Line l is (x−9)/7=y+3=−(z+1)/2(x-9)/7=y+3=-(z+1)/2, and plane p is 5x+3y+bz+1=05x+3y+bz+1=0.

    (i) If l and p meet in exactly one point, what can be said about b? marks

    Use b=1 for the rest.

    (ii) Find N, their intersection. marks

    (iii) Show the shortest distance from A to p is 35\sqrt{35}. marks

    (iv) Plane p1 is parallel to p at shortest distance 2352\sqrt{35}. Find a possible equation in scalar-product form. marks

    (v) Plane p undergoes, in order: translation 3 units in negative x; scaling parallel to the y-axis by factor 1/2; reflection in the xy-plane. Find a Cartesian equation of the resulting p2. marks

    [2016/CJC/Promo/12]

    CJC · Review problems · Question 8

  3. 9

    A,B have position vectors i−2j−k\mathbf i-2\mathbf j-\mathbf k and −i−2k-\mathbf i-2\mathbf k. Line l1 goes through A parallel to 5i+2j−k5\mathbf i+2\mathbf j-\mathbf k. Plane Π1 is r⋅(−1,1,2)=3\mathbf r\cdot(-1,1,2)=3.

    (i) Find the acute angle between l1 and Π1. marks

    (ii) Find the position vector of the perpendicular foot N from B to Π1. Hence find the reflected point B′. marks

    Plane Π2 contains B and l1.

    (iii) Find Π2 in scalar-product form. marks

    (iv) Find the Cartesian equation of intersection l2 of Π1,Π2. marks

    (v) Π3 is the reflection of Π2 in Π1. Find an equation r=u+sp+tq\mathbf r=\mathbf u+s\mathbf p+t\mathbf q, with s,t real. marks

    [2016/HCI/Promo/10]

    CJC · Review problems · Question 9

  4. 10

    A=(0,2,0), B=(1,0,2), and plane π1 is r⋅(2,2,1)=4\mathbf r\cdot(2,2,1)=4.

    (i) Find a vector equation of AB. marks

    (ii) Show AB lies in π1. mark

    (iii) Plane π2 contains AB and is perpendicular to π1. Show its equation is r⋅(−2,1,2)=2\mathbf r\cdot(-2,1,2)=2. marks

    (iv) P=(p,0,0) is equidistant from π1,π2. Calculate p. marks

    (v) Hence write down a line equidistant from π1,π2 which does not intersect either plane. marks

    [2016/MJC/Promo/9]

    CJC · Review problems · Question 10

  5. 11

    P has position vector 2i+j−2k2\mathbf i+\mathbf j-2\mathbf k and lies on ℓ:(1−y)/3=(z+2)/4\ell:(1-y)/3=(z+2)/4, x=2. Plane π1 is x−2y−2z=8x-2y-2z=8.

    (i) Show the intersection Q of ℓ,π1 is (2,7,−10). marks

    (ii) Find the exact sine of the acute angle between ℓ,π1. Hence find the exact length of projection of PQ onto π1. marks

    Plane π2 is parallel to π1. M has position vector 2i+(4α+4)j+(3α−6)k2\mathbf i+(4\alpha+4)\mathbf j+(3\alpha-6)\mathbf k and is equidistant from ℓ and π2.

    (iii) Find α if the distance from M to ℓ is 10. marks Hence deduce, when α>0, the Cartesian equation of π2. marks

    [2016/NYJC/Promo/10]

    CJC · Review problems · Question 11

  6. 12

    A=(4,1,0), and line l1 is x−3=−y=(z−3)/2x-3=-y=(z-3)/2.

    (i) Find plane π containing A and perpendicular to l1, in scalar-product form. marks

    (ii) Find P on l1 with AP perpendicular to l1. marks

    A ray travels along l2 from (0,−9,1) to P and reflects in π along l3, in the same plane as l1,l2, with equal angles between l1,l2 and l1,l3. Find l3. marks

    [2016/SAJC/Promo/11]

    CJC · Review problems · Question 12

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