Porisma

Vectors: planes, normals and distances

Learn one idea at a time

Choose a unit. Each has worked examples and practice.

  1. Describe a plane

    Choose between parametric, normal and Cartesian forms.

  2. Meet a line and a plane

    Decide whether a line crosses, misses or lies in a plane, then find its angle.

  3. Find perpendicular feet and distances

    Use the normal to find a foot and measure a distance.

  4. Compare two planes

    Find their separation, common line or acute angle.

Read or print the complete chapter

By the end, you can

  • Describe planes using normals or two directions
  • Find point-to-plane distance
  • Relate angles and intersections to vector products

4 focused units · about 40 minutes for the full chapter. Allow extra time for practice.

The central idea

A plane can be written n⋅r=c\mathbf n\cdot\mathbf r=c, where its nonzero normal vector is perpendicular to every direction in the plane. Equivalently, two independent in-plane directions give a parametric equation. The distance from P is ∣n⋅p−c∣/∣n∣|\mathbf n\cdot\mathbf p-c|/|\mathbf n|.

Derive a parametric plane

Choose a fixed point A with position a and two nonparallel nonzero directions b,c parallel to the plane. A displacement in the plane is AR→=λb+μc\overrightarrow{AR}=\lambda\mathbf b+\mu\mathbf c. Triangle addition gives OR→−OA→=AR→\overrightarrow{OR}-\overrightarrow{OA}=\overrightarrow{AR}, hence

r=a+λb+μc,λ,μ∈R.\mathbf r=\mathbf a+\lambda\mathbf b+\mu\mathbf c,\qquad\lambda,\mu\in\mathbb R.

This equation is not unique: another base point or independent pair of directions can describe the same plane. A drawn parallelogram is only a finite patch of an infinite plane and does not bound the real parameters. Parallel directions would not span a plane.

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Worked example

The plane x+2y+2z=9x+2y+2z=9 has normal (1,2,2)(1,2,2) with magnitude 3. The origin is distance ∣0−9∣/3=3|0-9|/3=3 from the plane. Its perpendicular foot is (1,2,2)(1,2,2).

The normal vector is perpendicular to the plane; it is not a direction lying in the plane.

Check your understanding

A point is P=(2,1,3)P=(2,1,3) and a plane is Π:x+2y+2z=1\Pi:x+2y+2z=1. Find the perpendicular foot F, the distance from P to the plane and the reflection Q of P in the plane. Verify the plane, direction and midpoint conditions. Explain why writing the plane as −x−2y−2z=−1-x-2y-2z=-1 must give the same results.

Full mastery checklist
Complete source practice map

Practice questions

40 examples and practice questions, in 7 sections.

More practice

Use geometry to choose a direction, normal or projection, then verify the resulting point in every required plane. Distinguish a line–plane angle from an angle between normals.

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