Reflect then reciprocate; translate then fold

The diagram below shows the graph of y=f(x)y=f(x). The curve cuts the axes at (−1,0)(-1,0) and (0,3)(0,3). It has a maximum point at (3,5)(3,5), and asymptotes x=−2x=-2 and y=2y=2.

Q4 original fxyOx=−2y=2(−1,0)(0,3)(3,5)
Question diagram 2
Q4 original fxyOx=−2y=2(−1,0)(0,3)(3,5)

Source graph with maximum (3,5) and asymptotes

Sketch on separate diagrams, the graphs of

(i) y=1f(−x)y=\frac1{f(-x)}; marks

(ii) y=∣f(x)−4∣y=|f(x)-4|. marks

showing clearly asymptotes, intercepts and coordinates of turning points, where available.

[modified 2010/ACJC/Prelim/I/3]

Total marks: 6

Solution

(i)

Reciprocal and reflection

Sketch the graph of y=1f(−x)y=\dfrac{1}{f(-x)}, showing clearly asymptotes, intercepts and coordinates of turning points, where available.

Explore this idea

Hint

  1. Find 1f(x)\frac{1}{f(x)} first: zeros become asymptotes, the maximum becomes a minimum.

  2. Then replace xx by −x-x: reflect in the yy-axis.

  3. Check the point where ff was undefined: what happens to 1f\frac1f there?

Q4(i) y=1/f(−x)
Q4(i) y=1/f(−x)Scroll across to see the full diagram.

Answer · (i)

Minimum (−3,1/5)(-3,1/5); intercept (0,1/3)(0,1/3); asymptotes x=1,y=1/2x=1,y=1/2; hole (2,0)(2,0).

No x-intercepts.

Explore the idea

Take the reciprocal, then reflect

The reciprocal reshapes the graph; the reflection then flips it left-right.

Teal: y = f(x). No comparison overlay.

Start: y = f(x)

The printed graph: (−1,0)(-1,0), (0,3)(0,3), maximum (3,5)(3,5), asymptotes x=−2x=-2 and y=2y=2.

  • Graph after the selected step
Ideas to try
  1. Follow the maximum of ff. It ends at the minimum (−3,1/5)(−3, 1/5).
  2. Which step creates the open point, and which one moves it?
(ii)

Translation and modulus

Sketch the graph of y=∣f(x)−4∣y=|f(x)-4|, showing clearly asymptotes, intercepts and coordinates of turning points, where available.

Explore this idea

Hint

  1. First draw y=f(x)−4y=f(x)-4. Which direction, and what happens to the asymptote?

  2. Then apply the modulus: reflect any part below the xx-axis upward.

  3. Where f(x)=4f(x)=4 the graph meets the xx-axis at a sharp point.

Correct answer: y=|f(x)−4|, including (−1,4)
Correct answer: y=|f(x)−4|, including (−1,4)Scroll across to see the full diagram.

Answer · (ii)

Local maximum (3,1)(3,1); points (0,1),(−1,4)(0,1),(-1,4); asymptotes x=−2,y=2x=-2,y=2.

Three sharp minima occur where f(x)=4; exact abscissae are unspecified.

Explore the idea

Slide down 4, then fold

After the shift, part of the curve is below the axis. The modulus flips exactly that part up.

Teal: y = f(x). No comparison overlay.

Start: y = f(x)

The printed graph: (−1,0)(-1,0), (0,3)(0,3), maximum (3,5)(3,5), asymptotes x=−2x=-2 and y=2y=2.

  • Graph after the selected step
Ideas to try
  1. Which parts of the second graph flip in the third? Is the maximum (3,1)(3,1) one of them?
  2. Count the sharp points on the xx-axis.