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Coverage & provenance · Recurrence relations

All coverage topics · Student practice

Indexing is not transcription, and transcription is not mathematical review. This page keeps those stages visible.

13Extracted numbered groups
13Authored explanations
13Recorded mathematical reviews
0Await authored conversion

13 of 13 groups have authored prompts and authored interactive lessons; 0 await conversion. 13 have mathematical review recorded. Review includes documented qualifications where the printed source is inconsistent or depends on an unstated assumption. This is a first authoring and mathematical review pass, not independent expert certification. Difficulty ratings remain unassigned. The ledger below distinguishes these states.

Inventory reconciliation: Inequalities Q13–14 are on question PDF page 3, printed page 22. Their extra indentation caused the initial scan to stop at Q12. The corrected topic count is 14 and the overall count is 248; original source bytes are unchanged.

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Collection-wide source ledger

248 complete-source articles and 15 topic metadata articles cover 468 original page instances. Source transcription, mathematical review and browser acceptance are recorded separately.

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Topic ledger

Question, answer, review and source-page counts for each topic.
TopicGroupsAuthored explanationsMaths reviewSource pages
13 · Recurrence relations1313 / 1313 / 135 question / 13 solution

Source qualifications and cautions

The original pages remain unchanged. Corrections, interpretation choices and necessary domain conditions are recorded alongside the authored working.

13-05 · reviewed

The limit substitution must first exclude the pole L=2; dividing by a denominator tending to zero is invalid.

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13-07 · reviewed

Finding possible limits does not prove convergence; every logarithm requires xnx_n>1.

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13-08 · reviewed

The source has a square root over 10−3xn10-3x_n; plain text extraction loses it. The recurrence is assumed defined and positive at every step.

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13-10 · reviewed

Use vn+1=vn/2v_{n+1}=v_n/2 rather than dividing by vnv_n, which could be zero.

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13-11 · reviewed

The printed question assumes convergence only in (i). Do not infer convergence of every sequence from the one-step inequalities.

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13-12 · reviewed

The denominator is 2 raised to xnx_n. Establishing an upper bound is necessary; increasing alone does not imply convergence.

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Series expansion topic 09 has byte-identical question and solution PDFs. Their printed solutions are transcribed once; the provenance ledger accounts for both file instances.

Exam references

2025 TJC H2 Maths (9758), JC2 MSM. Individual exam references are retained on question pages; original question and solution page numbers are kept independently. Source margin notes, short keys, tables and diagrams are transcribed into native articles. All 468 original page instances map to 2,703 native item records. Diagrams are source-specific D3 SVGs.

Owner reports that the source contributor has permission to republish. Original attribution and source-page provenance are retained. Originals are preserved privately for quality checks and are excluded from the delivered site.

Byte verification

Original ZIP: 11,692,621 bytes.

SHA-256: 39645f7e5aee1f8d870eca9267920157747d43725a1cc8b0486cb43ca532b1cc

30 PDFs / 468 PDF pages. Every PDF has its own byte length and SHA-256 in the manifest.

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Question-by-question status

Conversion, mathematical review and original question PDF page for every numbered group.
QuestionConversionMathematical reviewQuestion PDF pages
13-01 · Source reviewauthoredreviewed1
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13-12 · Source reviewauthoredreviewed4
13-13 · Source reviewauthoredreviewed4