Porisma
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Graph transformations

Practice section 6 of 9

Questions 31–36 in this collection

Practice questions

Worked example · 1 of 6

Compare curves with their reciprocals

Use a graphing calculator to sketch (a)(i) y=x+2y=x+2, (ii) y=1/(x+2)y=1/(x+2); (b)(i) y=(x+1)(x−3)y=(x+1)(x-3), (ii) y=1/((x+1)(x−3))y=1/((x+1)(x-3)). By comparing each pair, what do you observe about the relationship between y=f(x)y=f(x) and y=1/f(x)y=1/f(x)?

CJC · Transformations · Reciprocal activity

Solution

Worked example · 2 of 6

Reciprocate three supplied sketches

Given the three graphs of y=f(x)y=f(x), sketch the corresponding graphs of y=1/f(x)y=1/f(x). Indicate, if possible, the coordinates of the turning points, axial intercepts and asymptotes.

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Three given schematic graphs. (a) Positive bowl, minimum (0,a). (b) Horizontal asymptote y=a, vertical x=0, root −1/a, a>0 as drawn. (c) Pole x=−1, oblique y=x, local maximum (−2,−4) and local minimum (1/2,2). No unique formula for any graph is supplied.
Three given schematic graphs. (a) Positive bowl, minimum (0,a). (b) Horizontal asymptote y=a, vertical x=0, root −1/a, a>0 as drawn. (c) Pole x=−1, oblique y=x, local maximum (−2,−4) and local minimum (1/2,2). No unique formula for any graph is supplied.
Three given schematic graphs. (a) Positive bowl, minimum (0,a). (b) Horizontal asymptote y=a, vertical x=0, root −1/a, a>0 as drawn. (c) Pole x=−1, oblique y=x, local maximum (−2,−4) and local minimum (1/2,2). No unique formula for any graph is supplied.

CJC · Transformations · Example 17

Solution

Worked example · 3 of 6

Reciprocate a sketch with an excluded vertical limit

The curve shown has equation y=f(x)y=f(x). On a separate diagram, sketch y=1/f(x)y=1/f(x), indicating clearly the asymptotes and the coordinates of points corresponding to A(3,−1)A(3,-1) and B(1,0)B(1,0) where applicable.

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Given schematic y=f(x): left horizontal asymptote y=2, divergence upwards on both sides of x=0, root B(1,0), minimum A(3,−1), and right branch approaching y=0 from below. No formula is supplied.
Given schematic y=f(x): left horizontal asymptote y=2, divergence upwards on both sides of x=0, root B(1,0), minimum A(3,−1), and right branch approaching y=0 from below. No formula is supplied.
Given schematic y=f(x): left horizontal asymptote y=2, divergence upwards on both sides of x=0, root B(1,0), minimum A(3,−1), and right branch approaching y=0 from below. No formula is supplied.

CJC · Transformations · Example 18

Solution

Worked example · 5 of 6

Track five labelled points through eight transformations

The graph of y=f(x)y=f(x) is shown, with A(−1,0)A(-1,0), B(−0.549,−0.631)B(-0.549,-0.631), C(0,0)C(0,0), D(1.215,2.113)D(1.215,2.113) and E(2,0)E(2,0). On separate diagrams, sketch (a) y=f(x−2)y=f(x-2), (b) y=f(−x)+1y=f(-x)+1, (c) y=f(2x+1)y=f(2x+1), (d) y=2f(∣x∣)y=2f(|x|), (e) y=f(−∣x∣)y=f(-|x|), (f) y=∣f(x−2)∣y=|f(x-2)|, (g) y=f(∣x−2∣)y=f(|x-2|), (h) y=1/f(x)y=1/f(x). Indicate clearly, if possible, all coordinates of points corresponding to A, B, C, D and E.

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Given cubic-like graph with A(−1,0), B(−0.549,−0.631) local minimum, C(0,0), D(1.215,2.113) local maximum and E(2,0). Left tail rises and right tail falls. B/D are printed approximate data; no unique formula supplied.
Given cubic-like graph with A(−1,0), B(−0.549,−0.631) local minimum, C(0,0), D(1.215,2.113) local maximum and E(2,0). Left tail rises and right tail falls. B/D are printed approximate data; no unique formula supplied.
Given cubic-like graph with A(−1,0), B(−0.549,−0.631) local minimum, C(0,0), D(1.215,2.113) local maximum and E(2,0). Left tail rises and right tail falls. B/D are printed approximate data; no unique formula supplied.

CJC · Transformations · Example 19

Solution

Discussion practice · 6 of 6

Keep the order of horizontal translation and scaling

Explain how the graph of y=2/(3x−1)y=2/(3x-1) may be obtained from y=1/xy=1/x by appropriate transformations.

CJC · Discussion · Question 1

Solution

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