Definite integrals, areas and volumes
By the end, you can
- Interpret integrals as limits of sums and signed accumulation
- Calculate areas between curves
- Use discs or washers for volumes of revolution
about 30 minutes for the lesson · practise at your own pace.
The central idea
A definite integral accumulates signed contributions and can be evaluated by F(b)−F(a) when F′=f under the fundamental theorem. Geometric area is nonnegative, so split where the curve crosses an axis or two curves exchange order. Revolving a region produces cross-sectional discs or washers; integrate their areas.
Worked example
For on , . The geometric area is two triangles, each area 1/2, so total area is 1. Cancellation explains the difference.
A signed integral can be zero even when a region has positive area.
Check your understanding
The curves and enclose a finite region. Find its area and the volume when the region makes a full revolution about the x-axis. Establish the limits, identify the outer and inner radii, and explain why the two integrands differ.
The intersections satisfy , giving . Between them . The area is
The washer has outer radius and inner radius , so
Area accumulates vertical strip heights; volume accumulates cross-sectional washer areas. Squaring the height difference would give a different solid and is not the washer construction.
Mastery learning objectives
At the end of this chapter, I should be able to:
Choose a practice question
The source checkpoints are after lecture and after tutorial. Its area interpretation assumes a nonnegative curve with increasing bounds; in general a definite integral gives signed accumulation. For geometric area, split at sign changes and take the appropriate nonnegative contributions.
The source question map is reproduced below. Lecture references use the printed Example numbers; Discussion and Review refer to the chapter question sets. Blank cells mean the source gives no reference.
| Common question type | Lecture examples | Discussion | Review problems (follow up) |
|---|---|---|---|
| Definite integral as a process of summation | Q1, Q2 | Q1 | Q1 (first part), Q2 |
| Integration of ; source prints | Q3 | ||
| Definite integrals of , , or | Q3 | ||
| Partial fractions / splitting the numerator | Q2 | ||
| Piecewise function | Q4 | Q12(b) | |
| Integration by parts | Q5 | Q5(a) | Q4, Q6(a), Q7(b), Q8(a), Q11(i) |
| Integration by substitution | Q4, Q20(i) | Q7 (first part) | Q7(a) |
| Integration involving modulus | Q21 | Q6(b) | |
| Area | Q7, Q8, Q9, Q10, Q11, Q12, Q13, Q19(i), Q20(ii) | Q6, Q7(i) | Q5(a)(i), Q9(i)(iii), Q10(ii), Q11(iii), Q13, Q14(i) |
| Volume | Q14, Q15, Q16, Q17, Q18, Q19(ii) | Q5(b), Q7(ii), Q8, Q9 | Q1 (last part), Q5(a)(ii), Q8(b), Q9(ii), Q10(iii), Q11(iv), Q12(a), Q14(ii)(iii) |
Printed restriction correction: the power-rule row prints in both copies. For , the exceptional exponent is . At that exponent use on an interval where . Apply the real-domain conditions of the chosen power. The original printed wording remains retained in the native transcription.
Practice questions
50 examples and practice questions, in 9 sections.
More practice
Sketch the selected region or rate, identify any sign changes and choose the strip direction or radii. Interpret what the integral accumulates before calculating.
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