Rotate the region between a bell curve and a line
(i) Sketch and on the same diagram, showing clearly the coordinates of the stationary point and intersection points. marks
(ii) Find the exact area of region R enclosed by the curves and . marks
(iii) Find the volume generated when R is rotated about the -axis. marks
[2011/MI/Prelim/II/2]
Solution
If this part uses an earlier result, revisit (i) Curve sketching or open all working together.
Area between curves
Find the exact area of the region enclosed by the two curves and the lines and .
Hint
Each thin vertical strip of has height (curve) − (line).
Integrate that height from to .
“Exact” means the answer stays in terms of , so look for an arctangent.
Integrating only the curve gives . That measures the area all the way down to the -axis, not .
must be , not . Integration results are always in radians.
Answer · (ii)
Area .
Set up upper minus lower
Between and the curve lies above the line, so each strip has height .
Spot the arctangent
This is the standard result with and .
Substitute the limits
Use and , in radians.
Simplify and sense-check
The strips in the explorer above settle on the same number, which confirms the algebra.
Explore the idea
Open interactive exploration
Connect the parts: area × distance travelled
By the symmetry from (i), the centre of is at . Each turn carries that centre around a circle of length . Multiply by the area from (ii) and you get the volume from (iii):
This is Pappus’s centroid theorem. It is not on the syllabus, but it is a quick independent check of your answer.